PROCEDURE:-
1.enter an integer value n, set oddsum and evensum to 0
2. repeat step 3 and 4 until all the n different values are read
3.read an integer find modulo 2 of that if result is 0 add this to previous evensum
4.if result of modulo is 1 add the integer to previous oddsum
5.print the oddsum and evensum
CODE:-
#include<stdio.h>
void main()
{
int n,x,i=1;sume=0,sumo=0;
printf(“enter value for n”);
scanf(“%d”,&n);
printf(“enter %d different values”,n);
while(i<=n)
{
scanf(“%d”,&x);
if(x%2= =0)
sume=sume+x;
else
sumo=sumo+x;
i++
}
printf(“Even sum =%d \n Odd sum = %d”, sume,sumo);
}
Input:- enter value for n 4
enter 4 different values 10 11 12 13
Output:- Even sum =22 Odd sum =24
1.enter an integer value n, set oddsum and evensum to 0
2. repeat step 3 and 4 until all the n different values are read
3.read an integer find modulo 2 of that if result is 0 add this to previous evensum
4.if result of modulo is 1 add the integer to previous oddsum
5.print the oddsum and evensum
CODE:-
#include<stdio.h>
void main()
{
int n,x,i=1;sume=0,sumo=0;
printf(“enter value for n”);
scanf(“%d”,&n);
printf(“enter %d different values”,n);
while(i<=n)
{
scanf(“%d”,&x);
if(x%2= =0)
sume=sume+x;
else
sumo=sumo+x;
i++
}
printf(“Even sum =%d \n Odd sum = %d”, sume,sumo);
}
Input:- enter value for n 4
enter 4 different values 10 11 12 13
Output:- Even sum =22 Odd sum =24
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