PROCEDURE:-
1.set n=1
2. repeat steps 3 to 6 until n reaches 100
3.start finding modulo value for n with i=2 to n-1 value incrementing i by 1 each time
4.if at any point remainder becomes 0
5.don’t print that n
5.else print n
6.increment n by 1
CODE:-
#include<stdio.h>
void main()
{
int i,flag,n ;
printf(“primes below 100 are\n”);
for(n=1;n<=100;n++)
{
flag=0;
for(i=2;i<n;i++)
{
if (n % i = = 0)
{
flag=1;
break;
}
}
if (flag = = 0)
printf(“%3d “,n);
}
}
Output:-1,2,3,5,7,11,13,17,19, 23,………………97
1.set n=1
2. repeat steps 3 to 6 until n reaches 100
3.start finding modulo value for n with i=2 to n-1 value incrementing i by 1 each time
4.if at any point remainder becomes 0
5.don’t print that n
5.else print n
6.increment n by 1
CODE:-
#include<stdio.h>
void main()
{
int i,flag,n ;
printf(“primes below 100 are\n”);
for(n=1;n<=100;n++)
{
flag=0;
for(i=2;i<n;i++)
{
if (n % i = = 0)
{
flag=1;
break;
}
}
if (flag = = 0)
printf(“%3d “,n);
}
}
Output:-1,2,3,5,7,11,13,17,19,
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